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(3/5)^2x-9=1
We move all terms to the left:
(3/5)^2x-9-(1)=0
Domain of the equation: 5)^2x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+3/5)^2x-9-1=0
We add all the numbers together, and all the variables
(+3/5)^2x-10=0
We multiply all the terms by the denominator
(+3-10*5)^2x=0
We add all the numbers together, and all the variables
(-47)^2x=0
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